(6x^2-3x+2)-(6x^2+x-7)=0

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Solution for (6x^2-3x+2)-(6x^2+x-7)=0 equation:


Simplifying
(6x2 + -3x + 2) + -1(6x2 + x + -7) = 0

Reorder the terms:
(2 + -3x + 6x2) + -1(6x2 + x + -7) = 0

Remove parenthesis around (2 + -3x + 6x2)
2 + -3x + 6x2 + -1(6x2 + x + -7) = 0

Reorder the terms:
2 + -3x + 6x2 + -1(-7 + x + 6x2) = 0
2 + -3x + 6x2 + (-7 * -1 + x * -1 + 6x2 * -1) = 0
2 + -3x + 6x2 + (7 + -1x + -6x2) = 0

Reorder the terms:
2 + 7 + -3x + -1x + 6x2 + -6x2 = 0

Combine like terms: 2 + 7 = 9
9 + -3x + -1x + 6x2 + -6x2 = 0

Combine like terms: -3x + -1x = -4x
9 + -4x + 6x2 + -6x2 = 0

Combine like terms: 6x2 + -6x2 = 0
9 + -4x + 0 = 0
9 + -4x = 0

Solving
9 + -4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -4x = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4x = 0 + -9
-4x = 0 + -9

Combine like terms: 0 + -9 = -9
-4x = -9

Divide each side by '-4'.
x = 2.25

Simplifying
x = 2.25

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